Given the formula E = I x R, how many amps would be present with 126 volts and 10 ohms?

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Multiple Choice

Given the formula E = I x R, how many amps would be present with 126 volts and 10 ohms?

Explanation:
To find the current in amps using the formula \( E = I \times R \), where \( E \) stands for voltage (in volts), \( I \) represents current (in amps), and \( R \) is resistance (in ohms), you can rearrange the formula to solve for \( I \): \[ I = \frac{E}{R} \] Given that \( E = 126 \) volts and \( R = 10 \) ohms, you can substitute these values into the equation: \[ I = \frac{126 \text{ volts}}{10 \text{ ohms}} \] By performing the calculation: \[ I = 12.6 \text{ amps} \] Therefore, the presence of 12.6 amps in this scenario is correctly derived from the relationship defined in the formula. The calculations clearly show that the current, when the specified voltage and resistance are applied, results in 12.6 amps, affirming that this answer is accurate and consistent with Ohm's Law principles.

To find the current in amps using the formula ( E = I \times R ), where ( E ) stands for voltage (in volts), ( I ) represents current (in amps), and ( R ) is resistance (in ohms), you can rearrange the formula to solve for ( I ):

[ I = \frac{E}{R} ]

Given that ( E = 126 ) volts and ( R = 10 ) ohms, you can substitute these values into the equation:

[ I = \frac{126 \text{ volts}}{10 \text{ ohms}} ]

By performing the calculation:

[ I = 12.6 \text{ amps} ]

Therefore, the presence of 12.6 amps in this scenario is correctly derived from the relationship defined in the formula. The calculations clearly show that the current, when the specified voltage and resistance are applied, results in 12.6 amps, affirming that this answer is accurate and consistent with Ohm's Law principles.

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